AP EAMCET · PHYSICS · Current Electricity
Two square shaped metal plates of A and B of same thickness ( \(t\) ) and of same material are connected as shown in the figure. The side of \(B\) is twice that of \(A\). If the resistance of \(A\) and \(B\) are \(R_A\) and \(R_B\) respectively then \(\frac{\mathrm{R}_{\mathrm{A}}}{\mathrm{R}_{\mathrm{B}}}\) is
- A \(\frac{1}{2}\)
- B 2
- C 1
- D 4
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
\(\mathrm{L}_{\mathrm{A}}=\mathrm{L}\) and \(\mathrm{L}_{\mathrm{B}}=2 \mathrm{~L}\) then \(A_A=A\) and \(A_B=2 A\) By the formula of resistance \(\begin{aligned} & R=\frac{\rho L}{A} \\ & \frac{R_A}{R_B}=\frac{L_A A_B}{L_B A_A}=\frac{L}{2 L} \times \frac{2 A}{A}=1\end{aligned}\)
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