AP EAMCET · Maths · Properties of Triangles
In \(\triangle A B C\), the sum of the lengths of two sides is \(x\) and the product of those lengths is \(y\). If \(c\) is the length of its third side and \(x^2-c^2=y\), then the circumradius of that triangle is
- A \(\frac{\mathrm{c}}{\sqrt{3}}\)
- B \(\frac{c}{3}\)
- C \(\frac{y}{\sqrt{3}}\)
- D \(\frac{3 y}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{c}}{\sqrt{3}}\)
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