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AP EAMCET · Maths · Properties of Triangles

In ΔABC, if a:b:c=3:5:7, then cosA+cosB=

  1. A 137
  2. B 117
  3. C 127
  4. D 107
Verified Solution

Answer & Solution

Correct Answer

(C) 127

Step-by-step Solution

Detailed explanation

The ratio is given as, a:b:c=3:5:7. Considera=3x, b=5x, c=7x. Now, cosA+cosB=b2+c2-a22bc+a2+c2-b22ac =(5x)2+(7x)2-(3x)22(5x)(7x)+(3x)2+(7x)2-(5x)22(3x)(7x) =65x270x2+33x242x2 =6570+3342 =127
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