AP EAMCET · Maths · Differentiation
If \(y=\sin ^{98}(x) \cdot \cos ^{39}(x)\), then find \(\frac{d y}{d x}\)
- A \(\left(98 \cos ^{99} x \cdot \sin ^{38} x\right)+\left(39 \sin ^{40} x \cdot \cos ^{97} x\right)\)
- B \(\left(99 \cos ^{98} x \cdot \sin ^{39} x\right)-\left(40 \sin ^{39} x \cdot \cos ^{98} x\right)\)
- C \(\left(98 \cos ^{99} x \cdot \sin ^{38} x\right)-\left(39 \sin ^{40} x \cdot \cos ^{97} x\right)\)
- D \(\left.99 \cos ^{98} x \cdot \sin ^{39} x\right)+\left(39 \sin ^{40} x \cdot \cos ^{97} x\right)\)
Answer & Solution
Correct Answer
(C) \(\left(98 \cos ^{99} x \cdot \sin ^{38} x\right)-\left(39 \sin ^{40} x \cdot \cos ^{97} x\right)\)
Step-by-step Solution
Detailed explanation
\(y=\sin ^{98} x \cdot \cos ^{39} x\)…
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