AP EAMCET · Maths · Differentiation
If \(y=t^2+t^3\) and \(x=t-t^4\), then the value of \(\frac{d^2 y}{d x^2}\) at \(t=1\) is equal to
- A \(\frac{2}{3}\)
- B \(\frac{-2}{3}\)
- C \(\frac{4}{3}\)
- D \(\frac{-4}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{-4}{3}\)
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