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AP EAMCET · Maths · Application of Derivatives

If y=(ax-b)(x-1)(x-4) has a turning point P2,-1, then the values of a and b are

  1. A a=0, b=1
  2. B a=1, b=0
  3. C a=-1, b=0
  4. D a=0, b=-1
Verified Solution

Answer & Solution

Correct Answer

(B) a=1, b=0

Step-by-step Solution

Detailed explanation

Given, y=ax-bx-1x-4 …i has turning point P2,-1 ∴ Point P satisfy the equation i ⇒-1=2a-b2-12-4=2a-b-2 ⇒2a-b=2 …ii As we know turning point of function is a point where f'x=0. So, let's find dydx From equation i, yx-1x-4=ax-b…