AP EAMCET · Maths · Straight Lines
The equation of the side of an equilateral triangle is \(x+y=2\) and one vertex is \((2,-1)\). The length of the side is
- A \(\frac{\sqrt{2}}{\sqrt{3}}\)
- B \(\frac{1}{2 \sqrt{3}}\)
- C \(\frac{\sqrt{3}}{\sqrt{2}}\)
- D \(\frac{2}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{2}}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Given : \(x+y=2\) is equation of a side and \((2,-1)\) is vertex. Since \((2,-1)\) doesn't satisfy \(x+y=2\) \(\therefore \mathrm{It}\) is vertex opposite to the side. Perpendicular distance from \((2,-1)\) to \(x+y=2\) is height of the triangle…
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