AP EAMCET · Maths · Straight Lines
A point \(P(x, y)\) is such that its distance from \((-1,0)\) and \((0,2)\) are in a ratio of \(\sqrt{2}: 1\). Then the locus of \(\mathrm{P}\) is
- A \((x-1)^2+(y-4)^2=10\)
- B \((x+2)^2+(y+2)^2=10\)
- C \((x-1)^2+(y-4)^2=100\)
- D \((x+2)^2+(y+2)^2=100\)
Answer & Solution
Correct Answer
(A) \((x-1)^2+(y-4)^2=10\)
Step-by-step Solution
Detailed explanation
Given \(P(x, y),(-1,0)\) and \((0,2)\) Let \(A(-1,0)\) and \(B(0,2)\)…
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