AP EAMCET · Maths · Complex Number
If \(\log _{\frac{1}{\sqrt{3}}}\left\{\frac{|z|^2-|z|+1}{2+|z|}\right\}>-2\), then \(\mathrm{z}\) lies inside
- A a triangle
- B an ellipse
- C a circle
- D a square
Answer & Solution
Correct Answer
(C) a circle
Step-by-step Solution
Detailed explanation
Given that, \[ \log _{\frac{1}{\sqrt{3}}}\left\{\frac{|z|^2-|z|+1}{2+|z|}\right\}>-2 \] Since, \(\log _a b>c, b < a^c\) if \(0 < a < 1\)…
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