AP EAMCET · Maths · Hyperbola
If \(x=9\) is a chord of contact of the hyperbola \(x^2-y^2=9\), then the equation of the tangent at one of the points of contact is
- A \(x+\sqrt{3} y+2=0\)
- B \(3 x+2 \sqrt{2} y-3=0\)
- C \(3 x-\sqrt{2} y+6=0\)
- D \(x-\sqrt{3} y+2=0\)
Answer & Solution
Correct Answer
(B) \(3 x+2 \sqrt{2} y-3=0\)
Step-by-step Solution
Detailed explanation
Given that, \(x=9\) is a chord of contact of hyperbola. \[ \begin{aligned} & x^2-y^2=9 \\ & \text { put } x=9, \quad 81-y^2=9 \\ & \Rightarrow \quad y^2=72 \\ & \Rightarrow \quad y=6 \sqrt{2} \text { or }-6 \sqrt{2} \\ & \end{aligned} \] \(\therefore\) Points are…
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