AP EAMCET · Maths · Differentiation
If \(\log \sqrt{x^2+y^2}=\tan ^{-1}\left(\frac{x}{y}\right)\), then \(\frac{d y}{d x}\) is equal to
- A \(\frac{y-x}{y+x}\)
- B \(\frac{x+y}{x-y}\)
- C \(\frac{1}{y+x}\)
- D \(\frac{1}{x-y}\)
Answer & Solution
Correct Answer
(A) \(\frac{y-x}{y+x}\)
Step-by-step Solution
Detailed explanation
\(\log \sqrt{x^2+y^2}=\tan ^{-1}\left(\frac{x}{y}\right)\) Differentiate w.r.t ' \(x\) ' on both sides,…
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