AP EAMCET · Maths · Basic of Mathematics
If \(\frac{x^2+3}{x^4+2 x^2+9}=\frac{A x+B}{x^2+a x+b}+\frac{C x+D}{x^2+c x+b}\) then \(a A+b B+c C+D=\)
- A 1
- B 0
- C -1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(x^4+2 x^2+9\)…
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