AP EAMCET · Maths · Limits
If \(\lim _{x \rightarrow 0^{+}} x^2\left(\frac{e^{1 / x}-e^{-1 / x}}{e^{1 / x}+e^{-1 / x}}\right)=k\) and \(\lim _{x \rightarrow 0^{-}} x^2\left(\frac{e^{1 / x}-e^{-1 / x}}{e^{1 / x}+e^{-1 / x}}\right)=l\), then
- A \(k=1\)
- B \(k=1, I=-1\)
- C \(k=-1, /=1\)
- D \(k \neq I \neq \pm 1\)
Answer & Solution
Correct Answer
(A) \(k=1\)
Step-by-step Solution
Detailed explanation
\(k=\lim _{x \rightarrow 0^{+}} x^2\left[\frac{e^{\frac{1}{x}}-e^{\frac{-1}{x}}}{e^{\frac{1}{x}}+e^{\frac{-1}{x}}}\right]\) Let \(\frac{1}{x}=t\) \(x \rightarrow 0^{+}, t \rightarrow \infty\)…
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