AP EAMCET · Maths · Probability
The random variable \(\mathrm{X}\) has Binomial distribution \(\mathrm{B}(20,0.4)\). Then \(5-5 \mathrm{P}(\mathrm{X} \geq 2)=\)
- A \(62\left(\frac{2}{5}\right)^{19}\)
- B \(43\left(\frac{3}{5}\right)^{19}\)
- C \(1+23\left(\frac{3^{19}}{5^{20}}\right)\)
- D \(1+62\left(\frac{2^{19}}{5^{20}}\right)\)
Answer & Solution
Correct Answer
(B) \(43\left(\frac{3}{5}\right)^{19}\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{X}\) is a random variable with \(\mathrm{B}(20,0.4)\). So, \(x=20, P=0.4=\frac{4}{10}=\frac{2}{5}\). Then, \(q=1-\mathrm{P}=1-\frac{2}{5}=\frac{3}{5}\). Now,…
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