AP EAMCET · Maths · Probability
If two events A and B are such that \(\mathrm{P}(\overline{\mathrm{A}})=0.3, \mathrm{P}(\mathrm{B})=0.4\) and \(\mathrm{P}(\mathrm{A} \cap \overline{\mathrm{B}})=0.5\), then \(\mathrm{P}(\mathrm{B} /(\mathrm{A} \cup \overline{\mathrm{B}}))=\)
- A \(0.25\)
- B \(0.6\)
- C \(0.45\)
- D \(0.8\)
Answer & Solution
Correct Answer
(A) \(0.25\)
Step-by-step Solution
Detailed explanation
\(\mathrm{P}(\mathrm{A})=1-\mathrm{P}(\overline{\mathrm{A}})=1-0.3=0.7\) \(\mathrm{P}(\mathrm{A} \cap \mathrm{B})=\mathrm{P}(\mathrm{A})-\mathrm{P}(\mathrm{A} \cap \overline{\mathrm{B}})=0.7-0.5=0.2\)…
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