AP EAMCET · Maths · Pair of Lines
If the pair of straight lines \(6 x^2-5 x y+y^2=0\) makes angles \(\alpha\) and \(\beta\) with the \(X\)-axis, then \(\tan (\alpha-\beta)=\)
- A 2
- B \(\frac{1}{7}\)
- C 3
- D 7
Answer & Solution
Correct Answer
(B) \(\frac{1}{7}\)
Step-by-step Solution
Detailed explanation
\(6 x^2-5 x y+y^2=0\) \(\begin{aligned} & \Rightarrow \quad\left(\frac{y}{x}\right)^2-5\left(\frac{y}{x}\right)+6=0 \\ & \Rightarrow \quad\left(\frac{y}{x}-3\right)\left(\frac{y}{x}-2\right)=0 \\ \end{aligned}\) \(\Rightarrow \quad y=3 x\) and \(y=2 x\) are straight lines…
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