AP EAMCET · Maths · Vector Algebra
If the two diagonals of a parallelogram are \(\bar{i}+2 \bar{j}+3 \bar{k}\) and \(-2 \bar{i}+\bar{j}-2 \bar{k}\), then the area of the parallelogram in square units is
- A \(\frac{3}{2} \sqrt{5}\)
- B \(5 \sqrt{3}\)
- C \(\sqrt{300}\)
- D \(3 \sqrt{\frac{5}{2}}\)
Answer & Solution
Correct Answer
(D) \(3 \sqrt{\frac{5}{2}}\)
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