AP EAMCET · Maths · Probability
\(A\) speaks truth in \(75 \%\) of the cases and \(B\) in \(80 \%\) of the cases. Then, the probability that their statements about an incident do not match, is
- A \(\frac{7}{20}\)
- B \(\frac{3}{20}\)
- C \(\frac{2}{7}\)
- D \(\frac{5}{7}\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{20}\)
Step-by-step Solution
Detailed explanation
Let Event A: A speaks the truth Event B: B speaks the truth \(\begin{aligned} & P(A)=75 \%=\frac{75}{100}=\frac{3}{4} \\ & \text { and } P(B)=80 \%=\frac{80}{100}=\frac{4}{5} \end{aligned}\) \(\therefore \quad\) Required probability…
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