AP EAMCET · Maths · Circle
The equation of normal at \((1,1)\) to the circle \(x^2+y^2-x-3 y-4=0\) is
- A \(x+y-2=0\)
- B \(2 x-y-1=0\)
- C \(x-y+2=0\)
- D \(x-y-2=0\)
Answer & Solution
Correct Answer
(A) \(x+y-2=0\)
Step-by-step Solution
Detailed explanation
Circle is, \(x^2+y^2-x-3 y-4=0\) Slope of tangent at \((1,1)\) is obtained by differentiating above equation,…
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