AP EAMCET · Maths · Straight Lines
If the product of the perpendicular from origin to the pairs of lines \(x y+x+y+1=0\), \(x^2-y^2+2 x+1=0\) and \(2 x^2+3 x y\) \(-2 y^2+2 x+1=0\) respectively are \(p_1, p_2\) and \(p_3\), then
- A \(p_1 < p_2 < p_3\)
- B \(p_1 < p_3 < p_2\)
- C \(p_3 < p_2 < p_1\)
- D \(p_2 < p_1 < p_3\)
Answer & Solution
Correct Answer
(C) \(p_3 < p_2 < p_1\)
Step-by-step Solution
Detailed explanation
Given, \[ x y+x+y+1=0 \] Comparing above equation with \[ \begin{gathered} a x^2+b y^2+2 h x y+2 g x+2 f y+c=0 \\ a=0, b=0, h=\frac{1}{2}, g=\frac{1}{2}, f=\frac{1}{2}, c=1 \end{gathered} \] \(\because\) We know that, Product of perpendicular from origin to pair of straight…
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