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AP EAMCET · PHYSICS · Atomic Physics

If \(\Delta \lambda_L\) is the difference between shortest and longest wavelengths of Lymann series and \(\Delta \lambda_B\) is the difference between shortest and longest wavelengths of Balmer series, then \(\frac{\Delta \lambda_B}{\Delta \lambda_L}=\)

  1. A 2.4
  2. B 4.8
  3. C 7.2
  4. D 9.6
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Correct Answer

(D) 9.6

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