AP EAMCET · PHYSICS · Atomic Physics
If \(\Delta \lambda_L\) is the difference between shortest and longest wavelengths of Lymann series and \(\Delta \lambda_B\) is the difference between shortest and longest wavelengths of Balmer series, then \(\frac{\Delta \lambda_B}{\Delta \lambda_L}=\)
- A 2.4
- B 4.8
- C 7.2
- D 9.6
Answer & Solution
Correct Answer
(D) 9.6
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