AP EAMCET · Maths · Vector Algebra
\(\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{b}=2 \hat{i}+\hat{j}+\hat{k}\) are two vectors and \(\vec{c}\) is a unit vector lying in the plane of \(\vec{a}\) and \(\vec{b}\). If \(\vec{c}\) is perpendicular \(\vec{b}\). then \(\vec{c} \cdot(\hat{i}+\hat{j}+2 \hat{k})=\)
- A 0
- B 5
- C \(\frac{1}{\sqrt{21}}\)
- D \(\frac{2}{\sqrt{21}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{21}}\)
Step-by-step Solution
Detailed explanation
Vector lying in the plane of \(\vec{a} \& \vec{b}\) is…
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