AP EAMCET · Maths · Vector Algebra
For a non-zero real number \(x\), if the points with position vectors
\((x-u) \hat{\mathbf{i}}+x \hat{\mathbf{j}}+x \hat{\mathbf{k}}, x \hat{\mathbf{i}}+(x-v) \hat{\mathbf{j}}+x \hat{\mathbf{k}}\),
\(x \hat{\mathbf{i}}+x \hat{\mathbf{j}}+(x-w) \hat{\mathbf{k}}\) and
\((x-1) \hat{\mathbf{i}}+(x-1) \hat{\mathbf{j}}+(x-1) \hat{\mathbf{k}}\) are coplanar, then
- A \(u+v+w=1\)
- B \(u v w=1\)
- C \(\frac{1}{u}+\frac{1}{v}+\frac{1}{w}=1\)
- D \(u v+v w+u w=1\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{u}+\frac{1}{v}+\frac{1}{w}=1\)
Step-by-step Solution
Detailed explanation
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