AP EAMCET · Maths · Pair of Lines
If the pair of straight line given by \(A x^2+2 H x y+B y^2=0\), where \(\left(H^2>A B\right)\), forms an equilateral triangle with the line \(a x+b y+c=0\), then \((A+3 B)(3 A+B)=\)
- A \(4 H^2\)
- B \(2 H^2\)
- C \(-2 H^2\)
- D \(-4 H^2\)
Answer & Solution
Correct Answer
(A) \(4 H^2\)
Step-by-step Solution
Detailed explanation
According to the given information in the question the angle between lines represented by the equation \(A x^2+2 H x y+B y^2=0\) must be \(\frac{\pi}{3}\).…
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