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AP EAMCET · Chemistry · Ionic Equilibrium

The solubility of AgBr(s), having solubility product 5×10-10 in 0.2 M NaBr solution, equals

  1. A 5×10-10M
  2. B 25×10-10M
  3. C 0.5 M
  4. D 0.002 M
Verified Solution

Answer & Solution

Correct Answer

(B) 25×10-10M

Step-by-step Solution

Detailed explanation

Here, the solubility product Ksp of AgBr is 5×10-10 M. We know that for the reaction, AgBr → Ag++Br-Ksp = Ag+×Br- Also, it is given that the concentration of Br- is 0.2 M. Therefore,…