AP EAMCET · PHYSICS · Motion In One Dimension
If a stone thrown vertically upwards from a bridge with an initial velocity of \(5 \mathrm{~m} \mathrm{~s}^{-1}\), strikes the water below the bridge in a time of 3 s, then the height of the bridge above the water surface is
(Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 10 m
- B 26 m
- C 30 m
- D 18 m
Answer & Solution
Correct Answer
(C) 30 m
Step-by-step Solution
Detailed explanation
\(s = ut + \frac{1}{2}gt^2\) \(s = (-5)(3) + \frac{1}{2}(10)(3)^2\) \(s = -15 + 45 = 30 \mathrm{~m}\)
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