AP EAMCET · Maths · Parabola
If the normal at the point \(t_1\) (i.e., at \(\left.\left(a t_1^2, 2 \mathrm{at}_1\right)\right)\) on \(y^2=4 a x\) meets the parabola again at the point \(t_2\), then \(t_1 t_2=\)
- A \(-2-t_1^2\)
- B \(-2\)
- C \(-t_1^2+2\)
- D \(t_1^2+2\)
Answer & Solution
Correct Answer
(A) \(-2-t_1^2\)
Step-by-step Solution
Detailed explanation
Slope of normal at \(t_1\): \(-t_1\) Slope of chord joining \(t_1, t_2\): \(\frac{2at_2 - 2at_1}{at_2^2 - at_1^2} = \frac{2}{t_1+t_2}\) \(\frac{2}{t_1+t_2} = -t_1\) \(2 = -t_1(t_1+t_2)\) \(2 = -t_1^2 - t_1t_2\) \(t_1t_2 = -t_1^2 - 2\)
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