AP EAMCET · Maths · Area Under Curves
The area (in sq units) bounded by the curves
\(y^2=4 x\) and \(x^2=4 y\) is
- A \(\frac{64}{3}\)
- B \(\frac{16}{3}\)
- C \(\frac{8}{3}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{16}{3}\)
Step-by-step Solution
Detailed explanation
Given curves are \(y^2=4 x\) and \(x^2=4 y\). The intersection point is \(x^4=16 y^2=16(4 x)\) \(\begin{array}{rlrl}\Rightarrow & x\left(x^3-64\right) & =0 \\ \Rightarrow & & x & =0,4 \\ \Rightarrow & & y & =0,4\end{array}\) Hence, intersection point is \(O(0,0)\) and \(A(4,4)\)…
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