AP EAMCET · Maths · Statistics
If the mean deviation from the mean of the observations \(\{1+K \alpha\}\), where \(K=0,1,2, \ldots, 100\) and \(\alpha>0\) is 255 then \(\alpha=\)
- A \(10\)
- B \(10.1\)
- C \(25\)
- D \(25.5\)
Answer & Solution
Correct Answer
(B) \(10.1\)
Step-by-step Solution
Detailed explanation
\(\bar{x} = \frac{\sum_{K=0}^{100} (1+K\alpha)}{101} = \frac{101 + \alpha \frac{100 \times 101}{2}}{101} = 1+50\alpha\) \(\sum_{K=0}^{100} |(1+K\alpha)-(1+50\alpha)| = \sum_{K=0}^{100} |(K-50)\alpha| = \alpha \sum_{K=0}^{100} |K-50|\)…
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