AP EAMCET · Chemistry · Structure of Atom
The energies of an electron in first orbit of \(\mathrm{He}^{+}\)and in third orbit of \(\mathrm{Li}^{2+}\) in \(\mathrm{J}\) are respectively
- A \(-8.72 \times 10^{-18},-2.18 \times 10^{-18}\)
- B \(-8.72 \times 10^{-18},-1.96 \times 10^{-17}\)
- C \(-1.96 \times 10^{-17},-2.18 \times 10^{-18}\)
- D \(-8.72 \times 10^{-17},-1.96 \times 10^{-17}\)
Answer & Solution
Correct Answer
(A) \(-8.72 \times 10^{-18},-2.18 \times 10^{-18}\)
Step-by-step Solution
Detailed explanation
Key Idea Use relation: \[ E_n=-2.18 \times 10^{-18} \cdot \frac{Z^2}{n^2} \mathrm{~J} / \text { ion } \] where, \(E_n=\) energy of an electron in \(n\)th orbit \(Z=\) atomic number, \(n=\) orbit number For helium ion \(\left(\mathrm{He}^{+}\right)\)…
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