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AP EAMCET · Maths · Functions

If \(f:[0,3] \rightarrow[0,3]\) is defined by \(f(x)\) \(=\left\{\begin{array}{ll}1+x, & 0 \leq x \leq 2 \\ 3-x, & 2 < x \leq 3\end{array}\right.\), then fof is

  1. A Continuous at \(x=1\)
  2. B Continuous at \(x=2\)
  3. C Discontinuous at \(x=1\) and \(x=2\)
  4. D Continuous on \([0,3]\)
Verified Solution

Answer & Solution

Correct Answer

(C) Discontinuous at \(x=1\) and \(x=2\)

Step-by-step Solution

Detailed explanation

\[ \begin{gathered} g(x)=f(f(x))= \begin{cases}f(1+x) ; & 0 \leq x \leq 2 \\ f(3-x) & ; \quad 2 Using Eqs, (i), (ii), (iii), we get…