AP EAMCET · Maths · Circle
If the line \(4 x+4 y-11=0\) intersects the circle \(x^2+y^2-4 x-6 y+4=0\) at \(A\) and \(B\), then the point of intersection of the tangents drawn at \(A, B\) is
- A \((-1,2)\)
- B \((-1,-2)\)
- C \((2,1)\)
- D \((-2,-1)\)
Answer & Solution
Correct Answer
(D) \((-2,-1)\)
Step-by-step Solution
Detailed explanation
Let required point of intersection is \(\left(x_1, y_1\right)\), the equation of chord of contact with respect to given circle \(x^2+y^2-4 x-6 y+4=0\) is…
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