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AP EAMCET · Maths · Circle

If the equation of the circle lying in the first quadrant, touching both the coordinate axes and the line \(\frac{x}{3}+\frac{y}{4}=1\) is \((x-c)^2+(y-c)^2=c^2\), then \(c=\)

  1. A 1 or 4
  2. B 2 or 3
  3. C 1 or 6
  4. D 2 or 5
Verified Solution

Answer & Solution

Correct Answer

(C) 1 or 6

Step-by-step Solution

Detailed explanation

\(d = \frac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\) \(c = \frac{|4c+3c-12|}{\sqrt{4^2+3^2}}\) \(c = \frac{|7c-12|}{5}\) \(5c = 7c-12 \quad \text{or} \quad 5c = -(7c-12)\) \(-2c = -12 \quad \text{or} \quad 5c = -7c+12\) \(c = 6 \quad \text{or} \quad 12c = 12\)…