AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\frac{1}{\cos 290^{\circ}}+\frac{1}{\sqrt{3} \sin 250^{\circ}}=\)
- A \(\frac{\sqrt{3}}{4}\)
- B \(\frac{4}{\sqrt{3}}\)
- C \(\frac{2}{\sqrt{3}}\)
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Since } \frac{1}{\cos 290^{\circ}}+\frac{1}{\sqrt{3} \sin 250^{\circ}} \\ & =\frac{1}{\cos \left(270+20^{\circ}\right)}+\frac{1}{\sqrt{3} \sin \left(270-20^{\circ}\right)}\end{aligned}\)…
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