AP EAMCET · Maths · Parabola
If the line \(2 b x+3 c y+4 d=0\) passes through the points of intersection of \(y^2=4 a x\) and \(x^2=4 a y\), then
- A \(d^2+(2 b+3 c)^2=0\)
- B \(d^2+(3 b+2 c)^2=0\)
- C \(d^2+(2 b-3 c)^2=0\)
- D \(d^2+(3 b-2 c)^2=0\)
Answer & Solution
Correct Answer
(A) \(d^2+(2 b+3 c)^2=0\)
Step-by-step Solution
Detailed explanation
Given parabola, we have \[ x^2=4 a y \text { and } y^2=4 a x \] Intersection point of these two parabolas are \((0,0)\) and \((4 a, 4 a)\). Given that, \(2 b x+3 c y+4 d=0\) passes through point of intersection. Case I If it passes through \((0,0)\), we obtain…
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