AP EAMCET · Maths · Application of Derivatives
A is a point on the circle with radius 8 and centre at \(O\). A particle P is moving on the circumference of the circle starting from A. M. is the foot of the perpendicular from \(P\) on \(O A\) and \(\angle \mathrm{POM}=\theta\). When \(O M=4\) and \(\frac{d \theta}{d t}=6\) radians \(/ \mathrm{sec}\), then the rate of change of PM is (in units/sec)
- A \(24 \sqrt{3}\)
- B 24
- C \(15 \sqrt{3}\)
- D \(48 \sqrt{3}\)
Answer & Solution
Correct Answer
(B) 24
Step-by-step Solution
Detailed explanation
When \(O M=4 \Rightarrow \cos \theta=\frac{O M}{O P}=\frac{1}{2}\)…
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