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AP EAMCET · Maths · Application of Derivatives

A is a point on the circle with radius 8 and centre at \(O\). A particle P is moving on the circumference of the circle starting from A. M. is the foot of the perpendicular from \(P\) on \(O A\) and \(\angle \mathrm{POM}=\theta\). When \(O M=4\) and \(\frac{d \theta}{d t}=6\) radians \(/ \mathrm{sec}\), then the rate of change of PM is (in units/sec)

  1. A \(24 \sqrt{3}\)
  2. B 24
  3. C \(15 \sqrt{3}\)
  4. D \(48 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) 24

Step-by-step Solution

Detailed explanation

When \(O M=4 \Rightarrow \cos \theta=\frac{O M}{O P}=\frac{1}{2}\)…