AP EAMCET · Maths · Application of Derivatives
If the Lagrange's mean value theorem is applied to the function \(f(x)=e^x\) defined on the interval \([1,2]\) and the value of \(c \in(1,2)\) is \(k\), then \(e^{k-1}=\)
- A \(2\)
- B \(e-1\)
- C \(e+1\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(e-1\)
Step-by-step Solution
Detailed explanation
\(f'(c) = \frac{f(b)-f(a)}{b-a}\) \(e^c = \frac{e^2 - e^1}{2-1}\) \(e^k = e^2 - e\) \(e^{k-1} = \frac{e^k}{e} = \frac{e^2 - e}{e}\) \(e^{k-1} = e-1\)
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