AP EAMCET · Maths · Quadratic Equation
\(\alpha, \beta\) are the roots of \(x^2-10 x-8=0\) with \(\alpha>\beta\).
If \(\alpha_{\mathrm{n}}=\alpha^{\mathrm{n}}-\beta^{\mathrm{n}}\) for \(\mathrm{n} \in \mathbb{N}\), then the value of \(\frac{a_{10}-8 a_8}{5 a_9}\) is
- A \(-3\)
- B \(3\)
- C \(-2\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(x^2-10 x-8=0\) \(\begin{aligned} & x^2-8=10 x \\ & \frac{x^2-8}{5 x}=2\end{aligned}\) \(\alpha, \beta\) are roots \(\frac{\alpha^2-8}{5 \alpha}=2 \Rightarrow \alpha^2-8=10 \alpha\)...(i) \(\frac{\beta^2-8}{5 \beta}=2 \Rightarrow \beta^2-8=10 \beta\) ...(ii)…
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