AP EAMCET · Maths · Circle
If the circle \(x^2+y^2+6 x-2 y+k=0\) bisects the circumference of the circle \(x^2+y^2+2 x-6 y-15=0\), then \(k=\)
- A 21
- B -21
- C -23
- D 23
Answer & Solution
Correct Answer
(C) -23
Step-by-step Solution
Detailed explanation
Equation of given circles \[ \begin{array}{r} S_1: x^2+y^2+6 x-2 y+k=0 \\ \text { and } S_2: x^2+y^2+2 x-6 y-15=0 \end{array} \] Since, the circle \(S_1\) bisects the circumference of the circle \(S_2\), then the common of circles \(S_1\) and \(S_2\) will passing through the…
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