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AP EAMCET · Maths · Straight Lines

If the centroid of triangle whose vertices are \((a, 1,3)\), \((-2, \mathrm{~b},-5)\) and \((4,7, \mathrm{c})\) be the origin, then \(\mathrm{a}^2+\mathrm{b}^2+\mathrm{c}^2=\)

  1. A \(68\)
  2. B \(64\)
  3. C \(72\)
  4. D \(54\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(72\)

Step-by-step Solution

Detailed explanation

Centroid of triangle with vertices \(\left(x_1, y_1, z_1\right),\left(x_2, y_2\right.\),\(\left.z_2\right)\) and \(\left(x_3, y_3, z_3\right)\) is \(\left(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}, \frac{z_1+z_2+z_3}{3}\right)\) For \((a, 1,3),(-2, b,-5)(4,7, c)\); if…