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AP EAMCET · Maths · Three Dimensional Geometry

A plane passes through the point (3,5,7). If the direction ratios of its normal are equal to the intercepts made by the plane x+3y+2z=9 with the coordinate axes, then the equation of that plane is

  1. A x+y+z=5
  2. B 6x+2y+3z=105
  3. C 12x+4y+6z=49
  4. D 6x+2y+3z=49
Verified Solution

Answer & Solution

Correct Answer

(D) 6x+2y+3z=49

Step-by-step Solution

Detailed explanation

Given: x+3y+2z=9 ⇒x9+y3+z92=1 Comparing with the standard form xa+yb+zc=1, we get a=9→x-intercept b=3→y-intercept c=92→z-intercept So, the normal vector for the required plane is n→=9i^+3j^+92k^ a→=3i^+5j^+7k^ Equation of required plane,…