AP EAMCET · Maths · Circle
If the circle \(x^2+y^2+2 g x+2 f y+c=0(c>0)\) touches both the coordinate axes and lies in the third quadrant, then the length of the chord intercepted by the circle on the line \(x+y+\sqrt{c}=0\) is
- A \(\sqrt{2 \mathrm{C}}\)
- B \(\mathrm{C}\)
- C \(\sqrt{\mathrm{C}}\)
- D \(\sqrt{\frac{c}{2}}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{2 \mathrm{C}}\)
Step-by-step Solution
Detailed explanation
Given equation of circle \[ x^2+y^2+2 g x+2 f y+c=0 \quad(c>0) \] Coordinate of centre \(=(-g,-f)\) \[ \text { radius }=\sqrt{g^2+f^2-c} \] Circle touch both the axes, so \[ \begin{aligned} g^2 & =f^2=c \Rightarrow g= \pm \sqrt{c} \\ f & = \pm \sqrt{c} \end{aligned} \] So,…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If two unbiased six-faced dice are thrown simultaneously until a sum of either or occurs, then the probability that comes before isAP EAMCET 2019 Easy
- If and and if thenAP EAMCET 2018 Easy
- The center of ellipse \(x^2+2 y^2-4 x+12 y+14=0\) isAP EAMCET 2021 Easy
- Suppose \(X\) follows a binomial distribution with parameters \(n\) and \(p\), where \(0 < p < 1\). If \(\frac{P(X=r)}{P(X=n-r)}\) is independent of \(n\) for every \(r\), then \(p\) is equal toAP EAMCET 2012 Medium
- \(\begin{aligned} & \lim _{n \rightarrow \infty} n\left[\frac{1}{\left(3 n^2+8 n+4\right)}+\frac{1}{3 n^2+16 n+16}+\ldots\right. \\ & \left.+\frac{1}{15 n^2}\right]=\end{aligned}\)AP EAMCET 2018 Medium
- Let \(\mathbf{u}\) and \(\mathbf{v}\) be two vectors in a plane. Then any vector \(\mathbf{w}\) in the plane can be written as \(w=a \mathbf{u}+b \mathbf{v}\) for some scalars ' \(a\) ' and ' \(b\) ' if and only ifAP EAMCET 2020 Medium
More PYQs from AP EAMCET
- The elastic energy stored per unit volume in terms of longitudinal strain ' \(\epsilon\) ' and Young's modulus ' \(Y\) ' isAP EAMCET 2024 Easy
- Match the following List I with List II.
\(\begin{array}{|c|c|c|}
\hline & \text { List I } & \text { List II } \\
\hline \text { (A) } & \text { Transverse wave (i) } & \begin{array}{l}
\text {Vibrations parallel to the } \\
\text {direction of propagation }
\end{array} \\
\hline \text { (B) } & \begin{array}{l}
\text {Longitudinal wave }
\end{array} & \begin{array}{l}
\text {Vibrations perpendicular to } \\
\text {the direction of propagation }
\end{array} \\
\hline \text { (C) } & \text { Beats } & \begin{array}{l}
\text {Superposition of waves } \\
\text {travelling in the opposite directions }
\end{array} \\
\hline \text { (D) } & \text { Stationary waves (iv) } & \begin{array}{l}
\text {Superposition of waves } \\
\text {travelling in same direction }
\end{array} \\
\hline
\end{array}\)
The correct answer isAP EAMCET 2019 Easy - \(\lim _{x \rightarrow-\infty} \log _e(\cosh x)+x=\)AP EAMCET 2022 Medium
- If \(\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x=A \log \left|\cos \frac{x}{2}\right|+B \log \left|\cos \frac{x}{3}\right|+C \log \left|\cos \frac{x}{6}\right|+k\) then \(\mathrm{A}+\mathrm{B}+\mathrm{C}=\)AP EAMCET 2025 Medium
- The terminal velocity of a liquid drop of radius ' \(r\) ' falling through air is \(v\). If two such drops are combined to form a bigger drop, the terminal velocity with which the bigger drop falls through air is (ignore any buoyant force due to air)AP EAMCET 2013 Medium
- Two blocks of ice when pressed together join to form one block becauseAP EAMCET 2020 Easy