AP EAMCET · Maths · Indefinite Integration
If \(\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x=A \log \left|\cos \frac{x}{2}\right|+B \log \left|\cos \frac{x}{3}\right|+C \log \left|\cos \frac{x}{6}\right|+k\) then \(\mathrm{A}+\mathrm{B}+\mathrm{C}=\)
- A 7
- B 11
- C -7
- D 1
Answer & Solution
Correct Answer
(A) 7
Step-by-step Solution
Detailed explanation
\(\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x = \int \tan \frac{x}{2} \tan \frac{x}{3} \tan \frac{x}{6} d x\) Since \(\frac{x}{2} = \frac{x}{3} + \frac{x}{6}\), we use \(\tan(u+v) = \frac{\tan u + \tan v}{1 - \tan u \tan v}\) to get…
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