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AP EAMCET · Maths · Indefinite Integration

If \(\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x=A \log \left|\cos \frac{x}{2}\right|+B \log \left|\cos \frac{x}{3}\right|+C \log \left|\cos \frac{x}{6}\right|+k\) then \(\mathrm{A}+\mathrm{B}+\mathrm{C}=\)

  1. A 7
  2. B 11
  3. C -7
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(A) 7

Step-by-step Solution

Detailed explanation

\(\int \frac{1}{\cot \frac{x}{2} \cot \frac{x}{3} \cot \frac{x}{6}} d x = \int \tan \frac{x}{2} \tan \frac{x}{3} \tan \frac{x}{6} d x\) Since \(\frac{x}{2} = \frac{x}{3} + \frac{x}{6}\), we use \(\tan(u+v) = \frac{\tan u + \tan v}{1 - \tan u \tan v}\) to get…