AP EAMCET · Maths · Circle
If the chord \(x+y=1\) of the circle \(x^2+y^2=a^2\) subtends a right angle at the origin, then \(a=\)
- A 4
- B \(\sqrt{2}\)
- C 1
- D 2
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
\(x^2+y^2=a^2(x+y)^2\) \((1-a^2)x^2-2a^2xy+(1-a^2)y^2=0\) \((1-a^2)+(1-a^2)=0\) \(2(1-a^2)=0\) \(a^2=1\) \(a=1\)
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