AP EAMCET · PHYSICS · Electromagnetic Induction
A coil is placed in a time varying magnetic field. The power dissipated due to current induced in the coil is \(P_1\). If the number of turns is doubled and radius of the wire is halved, the power dissipated is \(P_2\). Then \(P_1: P_2\) is
- A 1 : 4
- B 3 : 2
- C 2 : 1
- D 4 : 1
Answer & Solution
Correct Answer
(A) 1 : 4
Step-by-step Solution
Detailed explanation
According to the question, radius of wire become \(\frac{r}{2}\), so its length will be \(4 l\) and its resistance will become \(16 R\). The number of turns is doubled in a coil, so its radius should be doubled to accomodate the length of wire. The area of coil will become 4…
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