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AP EAMCET · Maths · Application of Derivatives

If the area of a right angled triangle with hypotenuse 5 is maximum, then its perimeter is

  1. A \(12\)
  2. B \(2 \sqrt{3}+\sqrt{13}+5\)
  3. C \(7+\sqrt{21}\)
  4. D \(5(\sqrt{2}+1)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5(\sqrt{2}+1)\)

Step-by-step Solution

Detailed explanation

\(a^2+b^2=5^2\) Max area when \(a=b\): \(a^2+a^2=25 \Rightarrow 2a^2=25 \Rightarrow a=\frac{5}{\sqrt{2}}=\frac{5\sqrt{2}}{2}\) Perimeter \(P = a+b+c = \frac{5\sqrt{2}}{2}+\frac{5\sqrt{2}}{2}+5\) \(P = 5\sqrt{2}+5 = 5(\sqrt{2}+1)\)