AP EAMCET · Maths · Inverse Trigonometric Functions
If \(\operatorname{Tan}^{-1} \frac{1}{3}+\operatorname{Tan}^{-1} \frac{1}{7}+\operatorname{Tan}^{-1} \frac{1}{13}+\ldots+\operatorname{Tan}^{-1} \frac{1}{n^2+n+1}=\operatorname{Tan}^{-1} \theta\), then \(\theta=\)
- A \(\frac{n}{n+2}\)
- B \(\frac{n}{n+1}\)
- C \(\frac{n+1}{n+2}\)
- D \(\frac{n-1}{n+2}\)
Answer & Solution
Correct Answer
(A) \(\frac{n}{n+2}\)
Step-by-step Solution
Detailed explanation
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