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AP EAMCET · Maths · Inverse Trigonometric Functions

If \(\operatorname{Tan}^{-1} \frac{1}{3}+\operatorname{Tan}^{-1} \frac{1}{7}+\operatorname{Tan}^{-1} \frac{1}{13}+\ldots+\operatorname{Tan}^{-1} \frac{1}{n^2+n+1}=\operatorname{Tan}^{-1} \theta\), then \(\theta=\)

  1. A \(\frac{n}{n+2}\)
  2. B \(\frac{n}{n+1}\)
  3. C \(\frac{n+1}{n+2}\)
  4. D \(\frac{n-1}{n+2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{n}{n+2}\)

Step-by-step Solution

Detailed explanation

No solution. Refer to answer key.