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AP EAMCET · Maths · Circle

If \(\mathrm{Q}(h, k)\) is the inverse point of the point \(\mathrm{P}(1,2)\) with respect to the circle \(x^2+y^2-4 x+1-0\), then \(2 h+k=\)

  1. A \(3\)
  2. B \(4\)
  3. C \(7\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

Given equation of circle \(x^2+y^2-4 x+1=0\) \(\Rightarrow(x-2)^2+y^2=3\). So, centre \(=(2,0)\), radius \(=\sqrt{3}\) Now, inverse point is \(\mathrm{h}=\alpha(1-2)+2 \Rightarrow k=\alpha(2-0)+0\) where, \(\alpha=\frac{r^2}{(1-2)^2+(2-0)^2}=\frac{3}{1+4}=\frac{3}{5}\) Now,…