AP EAMCET · Maths · Circle
The equation of circle whose diameter is the diagonal of the rectangle with sides \(x=4, x=-2, y=5, y=-2\), is
- A \(x^2+y^2-2 x-3 y-18=0\)
- B \(x^2+y^2+2 x+3 y-18=0\)
- C \(x^2+y^2-2 x+3 y-18=0\)
- D \(x^2+y^2-2 x+3 y+18=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-2 x-3 y-18=0\)
Step-by-step Solution
Detailed explanation
Vertices of rectangle: \( (-2, -2) \) and \( (4, 5) \) are endpoints of diameter. Equation of circle: \( (x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0 \) \( (x - (-2))(x - 4) + (y - (-2))(y - 5) = 0 \) \( (x + 2)(x - 4) + (y + 2)(y - 5) = 0 \)…
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