AP EAMCET · Maths · Straight Lines
If \(P(\alpha, \beta)\) be a point on the line \(3 x+y=0\) such that the point \(P\) and the point \(Q(1,1)\) lie on either side of the line \(3 x=4 y+8\), then
- A \(\alpha>\frac{8}{15}, \beta < \frac{-8}{5}\)
- B \(\alpha < \frac{8}{15}, \beta < \frac{-8}{5}\)
- C \(\alpha>\frac{8}{15}, \beta>\frac{-8}{5}\)
- D \(\alpha < \frac{8}{15}, \beta>\frac{-8}{5}\)
Answer & Solution
Correct Answer
(A) \(\alpha>\frac{8}{15}, \beta < \frac{-8}{5}\)
Step-by-step Solution
Detailed explanation
Line \(L: 3 x=4 y+8\) \[ \begin{aligned} & =3 x-4 y-8 \\ L_{(1,1)} & =3-4-8=-9 0\)…
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